A Satellite revolving around the earth stays in its orbit because the Gravitational force is balanced by the centripetal force on the satellite.
or speed of the satellite v = √ GM/r
The speed v = Distance/Time = 2Πr/T = √ GM/r
Hence r³ = GMT²/4Π²
G is the gravitational constant (6.674×10−11 N · (m/kg)2)
M is the mass of earth 5.9736 x 1024 kg
T =86164.09 seconds which is earth's one rotation on its polar axis (23 hours, 56 Minutes and 4.1 seconds )
and the value of r = 42300 kilometres
M is the mass of earth 5.9736 x 1024 kg
T =86164.09 seconds which is earth's one rotation on its polar axis (23 hours, 56 Minutes and 4.1 seconds )
and the value of r = 42300 kilometres
By subtracting the radius of the earth 6,384 km we get height of the Geostationary orbit which is 35916 KM.
The Orbital speed of the satellite v= 3.0746 Km/s or 11068 Km/h
The orbit of geostationary is always Equatorial.
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